chinese

Mod(x, x^2 + 1)
Mod(x, x^4 - 1)
Mod(2, 3)*x^2 + Mod(1, 6)*x + Mod(1, 6)
[Mod(1, 4), Mod(1, 6)]
  ***   at top-level: chinese(1)
  ***                 ^----------
  *** chinese: incorrect type in association (t_INT).
Mod(0, 1)
Mod(x + 1, x^2)
Mod(x + 1, 2*x^2)
Mod(x + 1, x^2)
Total time spent: 0