mfdiv

Function: mfdiv
Section: modular_forms
C-Name: mfdiv
Prototype: GG
Help: mfdiv(F,G): compute F/G for two modular forms F and G assuming
 that the quotient will not have poles at infinity. If this is the
 case, use mfshift before doing the division.
Doc: Given two generalized modular forms $F$ and $G$, compute $F/G$ assuming
 that the quotient will not have poles at infinity. If this is the
 case, use \kbd{mfshift} before doing the division.
 \bprog
 ? D = mfDelta(); \\ Delta
 ? H = mfpow(mfEk(4), 3);
 ? J = mfdiv(H, D)
  ***   at top-level: J=mfdiv(H,mfdeltac
  ***                   ^--------------------
  *** mfdiv: domain error in mfdiv: ord(G) > ord(F)
 ? J = mfdiv(H, mfshift(D,1));
 ? mfcoefs(J, 4)
 %4 = [1, 744, 196884, 21493760, 864299970]
 @eprog