Book a Demo!
CoCalc Logo Icon
StoreFeaturesDocsShareSupportNewsAboutPoliciesSign UpSign In
Download

πŸ“š The CoCalc Library - books, templates and other resources

132928 views
License: OTHER
Kernel:
%%html <link href="http://mathbook.pugetsound.edu/beta/mathbook-content.css" rel="stylesheet" type="text/css" /> <link href="https://aimath.org/mathbook/mathbook-add-on.css" rel="stylesheet" type="text/css" /> <style>.subtitle {font-size:medium; display:block}</style> <link href="https://fonts.googleapis.com/css?family=Open+Sans:400,400italic,600,600italic" rel="stylesheet" type="text/css" /> <link href="https://fonts.googleapis.com/css?family=Inconsolata:400,700&subset=latin,latin-ext" rel="stylesheet" type="text/css" /><!-- Hide this cell. --> <script> var cell = $(".container .cell").eq(0), ia = cell.find(".input_area") if (cell.find(".toggle-button").length == 0) { ia.after( $('<button class="toggle-button">Toggle hidden code</button>').click( function (){ ia.toggle() } ) ) ia.hide() } </script>

Important: to view this notebook properly you will need to execute the cell above, which assumes you have an Internet connection. It should already be selected, or place your cursor anywhere above to select. Then press the "Run" button in the menu bar above (the right-pointing arrowhead), or press Shift-Enter on your keyboard.

ParseError: KaTeX parse error: \newcommand{\lt} attempting to redefine \lt; use \renewcommand

Section15.3Exercises

ΒΆ
1

What are the orders of all Sylow pp-subgroups where GG has order 18, 24, 54, 72, and 80?

Hint

If ∣G∣=18=2β‹…32,|G| = 18 = 2 \cdot 3^2\text{,} then the order of a Sylow 2-subgroup is 2, and the order of a Sylow 3-subgroup is 9.

2

Find all the Sylow 3-subgroups of S4S_4 and show that they are all conjugate.

Hint

The four Sylow 3-subgroups of S4S_4 are P1={(1),(123),(132)},P_1 = \{ (1), (123), (132) \}\text{,} P2={(1),(124),(142)},P_2 = \{ (1), (124), (142) \}\text{,} P3={(1),(134),(143)},P_3 = \{ (1), (134), (143) \}\text{,} P4={(1),(234),(243)}.P_4 = \{ (1), (234), (243) \}\text{.}

3

Show that every group of order 45 has a normal subgroup of order 9.

4

Let HH be a Sylow pp-subgroup of G.G\text{.} Prove that HH is the only Sylow pp-subgroup of GG contained in N(H).N(H)\text{.}

5

Prove that no group of order 96 is simple.

Hint

Since ∣G∣=96=25β‹…3,|G| = 96 = 2^5 \cdot 3\text{,} GG has either one or three Sylow 2-subgroups by the Third Sylow Theorem. If there is only one subgroup, we are done. If there are three Sylow 2-subgroups, let HH and KK be two of them. Therefore, ∣H∩K∣β‰₯16;|H \cap K| \geq 16\text{;} otherwise, HKHK would have (32β‹…32)/8=128(32 \cdot 32)/8 = 128 elements, which is impossible. Thus, H∩KH \cap K is normal in both HH and KK since it has index 2 in both groups.

6

Prove that no group of order 160 is simple.

7

If HH is a normal subgroup of a finite group GG and ∣H∣=pk|H| = p^k for some prime p,p\text{,} show that HH is contained in every Sylow pp-subgroup of G.G\text{.}

8

Let GG be a group of order p2q2,p^2 q^2\text{,} where pp and qq are distinct primes such that q∀p2βˆ’1q \nmid p^2 - 1 and p∀q2βˆ’1.p \nmid q^2 - 1\text{.} Prove that GG must be abelian. Find a pair of primes for which this is true.

Hint

Show that GG has a normal Sylow pp-subgroup of order p2p^2 and a normal Sylow qq-subgroup of order q2.q^2\text{.}

9

Show that a group of order 33 has only one Sylow 3-subgroup.

10

Let HH be a subgroup of a group G.G\text{.} Prove or disprove that the normalizer of HH is normal in G.G\text{.}

Hint

False.

11

Let GG be a finite group divisible by a prime p.p\text{.} Prove that if there is only one Sylow pp-subgroup in G,G\text{,} it must be a normal subgroup of G.G\text{.}

12

Let GG be a group of order pr,p^r\text{,} pp prime. Prove that GG contains a normal subgroup of order prβˆ’1.p^{r-1}\text{.}

13

Suppose that GG is a finite group of order pnk,p^n k\text{,} where k<p.k \lt p\text{.} Show that GG must contain a normal subgroup.

14

Let HH be a subgroup of a finite group G.G\text{.} Prove that gN(H)gβˆ’1=N(gHgβˆ’1)g N(H) g^{-1} = N(gHg^{-1}) for any g∈G.g \in G\text{.}

15

Prove that a group of order 108 must have a normal subgroup.

16

Classify all the groups of order 175 up to isomorphism.

17

Show that every group of order 255255 is cyclic.

Hint

If GG is abelian, then GG is cyclic, since ∣G∣=3β‹…5β‹…17.|G| = 3 \cdot 5 \cdot 17\text{.} Now look at ExampleΒ 15.14.

18

Let GG have order p1e1β‹―pnenp_1^{e_1} \cdots p_n^{e_n} and suppose that GG has nn Sylow pp-subgroups P1,…,PnP_1, \ldots, P_n where ∣Pi∣=piei.|P_i| = p_i^{e_i}\text{.} Prove that GG is isomorphic to P1Γ—β‹―Γ—Pn.P_1 \times \cdots \times P_n\text{.}

19

Let PP be a normal Sylow pp-subgroup of G.G\text{.} Prove that every inner automorphism of GG fixes P.P\text{.}

20

What is the smallest possible order of a group GG such that GG is nonabelian and ∣G∣|G| is odd? Can you find such a group?

21The Frattini Lemma

If HH is a normal subgroup of a finite group GG and PP is a Sylow pp-subgroup of H,H\text{,} for each g∈Gg \in G show that there is an hh in HH such that gPgβˆ’1=hPhβˆ’1.gPg^{-1} = hPh^{-1}\text{.} Also, show that if NN is the normalizer of P,P\text{,} then G=HN.G= HN\text{.}

22

Show that if the order of GG is pnq,p^nq\text{,} where pp and qq are primes and p>q,p>q\text{,} then GG contains a normal subgroup.

23

Prove that the number of distinct conjugates of a subgroup HH of a finite group GG is [G:N(H)].[G : N(H) ]\text{.}

Hint

Define a mapping between the right cosets of N(H)N(H) in GG and the conjugates of HH in GG by N(H)g↦gβˆ’1Hg.N(H) g \mapsto g^{-1} H g\text{.} Prove that this map is a bijection.

24

Prove that a Sylow 2-subgroup of S5S_5 is isomorphic to D4.D_4\text{.}

25Another Proof of the Sylow Theorems
  1. Suppose pp is prime and pp does not divide m.m\text{.} Show that

    p∀(pkmpk).\begin{equation*} p \nmid \binom{p^k m}{p^k}. \end{equation*}
  2. Let S{\mathcal S} denote the set of all pkp^k element subsets of G.G\text{.} Show that pp does not divide ∣S∣.|{\mathcal S}|\text{.}

  3. Define an action of GG on S{\mathcal S} by left multiplication, aT={at:t∈T}aT = \{ at : t \in T \} for a∈Ga \in G and T∈S.T \in {\mathcal S}\text{.} Prove that this is a group action.

  4. Prove p∀∣OT∣p \nmid | {\mathcal O}_T| for some T∈S.T \in {\mathcal S}\text{.}

  5. Let {T1,…,Tu}\{ T_1, \ldots, T_u \} be an orbit such that p∀up \nmid u and H={g∈G:gT1=T1}.H = \{ g \in G : gT_1 = T_1 \}\text{.} Prove that HH is a subgroup of GG and show that ∣G∣=u∣H∣.|G| = u |H|\text{.}

  6. Show that pkp^k divides ∣H∣|H| and pkβ‰€βˆ£H∣.p^k \leq |H|\text{.}

  7. Show that ∣H∣=∣OTβˆ£β‰€pk;|H| = |{\mathcal O}_T| \leq p^k\text{;} conclude that therefore pk=∣H∣.p^k = |H|\text{.}

26

Let GG be a group. Prove that Gβ€²=⟨abaβˆ’1bβˆ’1:a,b∈G⟩G' = \langle a b a^{-1} b^{-1} : a, b \in G \rangle is a normal subgroup of GG and G/Gβ€²G/G' is abelian. Find an example to show that {abaβˆ’1bβˆ’1:a,b∈G}\{ a b a^{-1} b^{-1} : a, b \in G \} is not necessarily a group.

Hint

Let aGβ€²,bGβ€²βˆˆG/Gβ€².a G', b G' \in G/G'\text{.} Then (aGβ€²)(bGβ€²)=abGβ€²=ab(bβˆ’1aβˆ’1ba)Gβ€²=(abbβˆ’1aβˆ’1)baGβ€²=baGβ€².(a G')( b G') = ab G' = ab(b^{-1}a^{-1}ba) G' = (abb^{-1}a^{-1})ba G' = ba G'\text{.}